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In an ac circuit , L = (0.4)/(pi) H and ...

In an ac circuit , `L = (0.4)/(pi) H` and `R = 30 Omega`. If the circuit has an alternating emf of 220 V, 50 cps, the impedance and the current in the circuit will be :

A

`11.4 Omega`,17.5 A

B

`30.7 Omega, 6.5 A

C

`40.4 Omega`, 5 A

D

`50 Omega`, 4 A

Text Solution

Verified by Experts

The correct Answer is:
D
Given , `underset(L)(X)` = `omegaL = 2pifL = 2pi xx 50 xx 0.4/pi = 40 Omega`
R = 30`Omega`
Z = `sqrt R^(2) = sqrt (30)^(2) + (40)^(2)` = `50Omega`
`underset(rms)(I)` = `underset(rms)(V)/Z = 200 / 50` = 4 A
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