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An L-C-R series is under resonance . If ...

An L-C-R series is under resonance . If `underset(m)(l)` is current amplitude `underset(m)(V)` is voltage amplitude, R is the resonance , Z is the impedance , `underset(L)(X)` is the inducitve reactance and `underset( C )(X) ` is the capacitive reactance , then

A

`underset(m)(l)` = `underser(m)(V)`/ Z

B

`underset(m)(V)`/ `underset(L)(X)`

C

`underset(m)(l)` = `underset(m)(V)` / `underset( C )(X)`

D

`underset(m)(l)` = `underset(m)(V)` / R

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The correct Answer is:
D
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