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The average power dissipated in a pure i...

The average power dissipated in a pure inductor `L carrying an alternating current of rms value I is .

A

1/2` Li^(2)`

B

1/4`Li^(2)`

C

2`Li^(2)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D
In case of a pure inductance , R = 0
Power factor = cos`phi` = R/Z = 0/X = 0
So, `underset(av)(P)` = `underset(rms)(E)`.`underset(rms)(i)` `xx` 0 = 0
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