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The resonant frequency of a circuit is f...

The resonant frequency of a circuit is `f`. If the capacitance is made `4` times the initial values, then the resonant frequecy will become

A

f/2

B

2f

C

f

D

f/4

Text Solution

Verified by Experts

The correct Answer is:
A
Resonant frequency , f = 1/`2pi``sqrt LC`
f `propto` 1/`sqrt C` or `underset(1)(f)` / `underset(2)(f)` = `sqrt underset(2)(C )/underset(1)(C )`
`implies` f/`underset(2)(f)` = `sqrt 4C/C ` `implies` `underset(2)(f)` = f/2
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