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A lamp consumes only 50% of peak power i...

A lamp consumes only `50%` of peak power in an `a.c.` circuit. What is the phase difference between the applied voltage and the circuit current

A

`pi`/6

B

`pi`/3

C

`pi`/4

D

`pi`/2

Text Solution

Verified by Experts

The correct Answer is:
B
P = 1/2 `underset(o)(V)``underset(o)(I)`cos`phi`
`implies` P = `underset(peak)(P)` cos`phi`
`implies` 1/2(`underset(peak)(p)` = `underset(peak)(p)` cos`phi`
`=lt` cos`phi` = 1/2 `implies` 1/2 `implies` `phi` = `pi`/3
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