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An alternating voltage is given by: e = ...

An alternating voltage is given by: `e = e_(1) sin omega t + e_(2) cos omega t`. Then the root mean square value of voltage is given by:

A

`sqrt(e_(1)^(2)+e_(2)^(2))`

B

`sqrt(e_(2)e_(2))`

C

`sqrt(e_(1)e_(2))/(2)`

D

`sqrt(e_(1)^(2)+e_(2)^(2))/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
d) `e=sqrt(e_(1)^(2)+e_(2)^(2))sin(omegat+phi)`
Where, `cosphi = (e_(1))/(sqrt(e_(1)^(2)+e_(2)^(2)))` and `sinphi = (e_(2))/(sqrt(e_(1)^(2)+e_(2)^(2)))`
i.e., `e_(0) = sqrt(e_(1)^(2)+e_(2)^(2))`
or `e_(rms) = sqrt(e_(1)^(2)+e_(2)^(2))/(sqrt(2))`
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