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Two coils have a mutual inductance 0.005...

Two coils have a mutual inductance 0.005 H. The alternating current charges in the first coil according to equation I = `underset(o)(I)`sin`omega`t, where `underset(o)(I)` = 10 A amd `omega` = 100`pi` `rads^(-1)`. The maximum value of emf in the second coil
is (in volt)

A

`2pi`

B

`5pi`

C

`pi`

D

`4pi`

Text Solution

Verified by Experts

The correct Answer is:
B
Value of induced emf in coil
e = M di/dt
= 0.005 xx d/dt(`underset(o)(I) omega cos omega` t)
0.005 `xx` `underset(o)(I)``omega` cos `omega`t
`therfore` `underset(max)(e)` = `0.005 xx 10 xx 100pi` = `5pi`
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