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In an circuit, V and I are given by V=15...

In an circuit, V and I are given by `V=150sin(150t) V` and `I =150sin(150t+(pi)/(3))A`. The power dissipated in the circuit is

A

106 W

B

150W

C

5625 W

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
Given, `V=150sin(150t)V`
and `I=150sin(150t+pi//3)A`
`therefore I_(0) = 150 A` and `V_(0) = 150V`
Power, `P=1/2 V_(0) I_(0)cosphi`
`rArr P=0.5 xx 150 xx 150 xx cos60^(@)`
`rArr P=5625W`
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