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The natural frequency of the circuit sho...

The natural frequency of the circuit shown in the figure is

A

`1/2pi sqrt LC`

B

`1/2pi sqrt 2LC`

C

`2/2pi sqrt LC`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(net)(C )= c/2(in series)` and `underset(net)(L) = 2L (in series)`
`therefore omega = 1/sqrt underset(net)(L)underset(net)(C )`or `f = 1/2pisqrt (2L).(C/2)` or f = `1/2pisqrt LC`
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