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Current in resistance is 1 A , then...

Current in resistance is 1 A , then

A

`underset(s)(V)` = 5 V

B

impedance of network is `5 Omega`

C

power factor of given circuit is (0.6) lagging (current is lagging )

D

All the above

Text Solution

Verified by Experts

The correct Answer is:
D
`V_S^(2)` = `(3)^(2)` + `(8 - 4)^(2)` , `V_S` = 5 v
Now, Z = `V_S`/t = 5/t = 5 `Omega`
Also, `V_R` = IR or R = 3/1 = `3 Omega`
So, PF = R/Z = 0.6 as `V_L gt V_C`
`implies` I lags V, so this a lagging nature.
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