Home
Class 12
PHYSICS
A capacitor of capacitance 1 muF is char...

A capacitor of capacitance `1 muF` is charged to a potential of `1 V`, it is connected in parallel to an inductor of inductance `10^(-3)H`. The maximum current that will flow in the circuit has the value

A

`sqrt 1000` mA

B

1A.

C

1 mA

D

1000 mA

Text Solution

Verified by Experts

The correct Answer is:
A
Change the capacitor,
`q_0 = CV = 1 xx 10^(-6) xx 1 = 10^(-4)` C
`implies` Here, q = 'q _0sin omegat`
or `I_0 = omega q_0 =` maximum current.
`therefore I_0 = (10^(9)^(t/2)) xx (1 xx 10^(-6) = sqrt 1000` mA.
Promotional Banner

Similar Questions

Explore conceptually related problems

A capasitor of capacitance 1 (mu)F is charged to a potential of 1 V, it is connected in parallel to an inductor of inductance 10^(-3)H . The maximum current that will flow in the circuit has the value

A capacitor of capacity 2 muF is charged to a potential difference of 12 V . It is then connected across an inductor of inductance 6 mu H . What is the current (in A ) in the circuit at a time when the potential difference across the capacitor is 6.0 V ?

A capacitor of capacitance 100 mu F is charged to a potential of "12V" and connected to a 6.4mH inductor to produce oscillations.The maximum current in the circuit would be

A capacitor of capacity 2muF is changed to a potential different of 12V . It is then connected across an inductor of inductance 0.6mH What is the current in the circuit at a time when the potential difference across the capacitor is 6.0V ?

Calculate the maximum current in the circuit, if a capacitor of capacitance 1muF is charged to a potential of 2 V and is connceted in parallel to an inductor of inductance 10^(-3)H .

A capacitor of capacitance 1 mu F is charged to potential 2 V and is connected to an inductor of 1 mH. At an instant when potential difference across. The capacitor is 1 V, the current in the circuit is 10^(-2) sqrt((10x)/(3)) ampere. Find out the value of x.

A capacitor of capacitance 1 mu F is charged to a potential of 20 volt. The battery is then disconnected and a pure inductive coil of inductance 10 mH is connected across the capacitor so that L-C oscillation are set-up in the circuit. What is the maximum current in the circuit?