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In an AC, series L-C-R circuit, R=X(L)=X...

In an AC, series L-C-R circuit, `R=X_(L)=X_(C)` and applied AC, voltage is V. Then match the following two columns.

Text Solution

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The correct Answer is:
(A-q); (B-q); (C-r); (D-p)
Z=R [As `X_(L)=X_(C))]`
`therefore I=V/Z=V/R`
Now, `V_(R) = IR=V`
`V_(C) = IX_(C)=V=V_(L)`
`V_(RL) = sqrt(V^(2)+V^(2)) = sqrt(2)V`
`V_(LC) = V-V=0`
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