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A 0.01 H inductor and sqrt(3)pi Omega re...

A 0.01 H inductor and `sqrt(3)pi Omega` resistance are connected in series with a 220 V, 50 Hz AC source. The phase difference between the current and emf is

A

`pi/2rad`

B

`pi/6` rad

C

`pi/3` rad

D

*-

Text Solution

Verified by Experts

The correct Answer is:
B
`phi = tan^(-1)((X_(L))/R) = tan^(-1)((2pivL)/R)`
`=(tan^(-1))((2pi xx 50xx0.01))/(sqrt(3pi))=tan^(-1)(1/(sqrt(3))) = pi/6rad`
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