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For a series L-C-R circuit with L=1.00 m...

For a series L-C-R circuit with L=1.00 mH, C=10`muF` and `R=50Omega`, is driven with 5V AC voltage. At resosance, the current through the circuit is

A

0.2 A

B

0.25 A

C

0.15 A

D

0.1 A

Text Solution

Verified by Experts

The correct Answer is:
D
We know that for series L-C-R in circuit.
`V_(rms) = sqrt(V_(R)^(2) + (V_(L)-V_(C)^(2)))`
Given, `V_(L)`= 90V, `V_(C)` = 60V
and `V_(R)` = 40 V
Now, `V_(rms) = sqrt((40)^(2)+(90-60)^(2))`=50 V
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