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A series circuit connected across a 200 ...

A series circuit connected across a `200 V, 60 Hz` line consists of a capacitive reactance `30 Omega` non inductive resistor of `44 Omega` and a coil of inductive reactance `90 Omega` and resistance `36 Omega` as shown in the diagram

The power dissipated in the inductance coil is

A

320 W

B

176 W

C

144 W

D

0

Text Solution

Verified by Experts

The correct Answer is:
A

We have, `X_(L) = 90 Omega`, `X_(C) = 30 Omega`
and `R=R_(1)+R_(2)=44+36=80Omega`
Impedance , `Z=sqrt(R^(2) + (X_(L)-X_(C))^(2))`
`=sqrt((80)^(2)+(60)^(2))`
`Z=sqrt(6400 + 3600) = 100 Omega`
`I=V/Z = 200/100 = 2A`
`P_(av) = I^(2)R= (2)^(2) xx 80 = 320 W`
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