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A parallel plate capacitor of plate sepa...

A parallel plate capacitor of plate separation `2 mm` is connected in an electric circuit having source voltage `400 V`. If the plate area is `60 cm^(2)`, then the value of displacement current for `10^(-6) sec` will be

A

`1.062 xx 10^(-2) A`

B

`2.062 xx 10^(-2) A`

C

`3.062 xx 10^(-2) A`

D

`5.062 xx 10^(-2) A`

Text Solution

Verified by Experts

The correct Answer is:
A
Displacement current, `I_(d) = epsi_(0)(dphi)/(dt)`
`= epsi_(0)(EA)/(t) = (epsi_(0)(V//d)xxA)/(t) = (epsi_(0)VA)/(td)`
`= (8.85 xx 10^(-12) xx 400 xx (60 xx 10^(-4)))/(10^(-6) xx (2 xx 10^(-3)))`
`= 1.062 xx 10^(-2) A`
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