In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of `2xx10^(10)Hz` and amplitude `48V//m`. The wavelength of the wave will be-

Options

A. `24 xx 10^(-10) m`
B. `1.5 xx 10^(-2) m`
C. `4.16 xx 10^(8) m`
D. `3 xx 10^(8)m`

Answer

B

Explanation

`:'` Speed, `c = mulambda`
`:.` wavelength `lambda = (c)/(v) =(3 xx 10^(8))/(2 xx 10^(10)) = 1.5 xx 10^(-2) m`