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The pressure exerted by an electromagnet...

The pressure exerted by an electromagnetic wave of intensity `I (Wm^(-2))` on a non-reflecting surface is ( c is the velocity of light)

A

`Ic`

B

`Ic^(2)`

C

`I//c`

D

`I//c^(2)`

Text Solution

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The correct Answer is:
To find the pressure exerted by an electromagnetic wave of intensity \( I \) on a non-reflecting surface, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: We are given an electromagnetic wave with intensity \( I \) (in watts per square meter) striking a non-reflecting surface. We need to determine the pressure exerted by this wave on the surface. 2. **Concept of Pressure**: Pressure \( P \) is defined as the force \( F \) per unit area \( A \): \[ P = \frac{F}{A} \] 3. **Force from Momentum Change**: The force exerted by the electromagnetic wave can be related to the change in momentum. The electromagnetic wave carries momentum, and when it strikes a surface, it transfers momentum to that surface. The force can be expressed as the rate of change of momentum: \[ F = \frac{dP}{dt} \] 4. **Momentum Transfer**: For a non-reflecting surface, the entire momentum of the wave is absorbed. The change in momentum \( \Delta P \) when the wave is absorbed can be related to the intensity \( I \) of the wave. The intensity \( I \) is defined as the energy per unit time per unit area: \[ I = \frac{E}{A \cdot \Delta t} \] where \( E \) is the energy. 5. **Relating Energy to Momentum**: The momentum \( P \) of the electromagnetic wave can be related to its energy \( E \) by the equation: \[ P = \frac{E}{c} \] where \( c \) is the speed of light. 6. **Calculating Pressure**: Since the force is the rate of change of momentum, we can substitute the expression for momentum into the force equation: \[ F = \frac{d}{dt}\left(\frac{E}{c}\right) = \frac{1}{c} \frac{dE}{dt} \] The term \( \frac{dE}{dt} \) is the power, which is equal to the intensity \( I \) multiplied by the area \( A \): \[ \frac{dE}{dt} = I \cdot A \] Thus, we can rewrite the force as: \[ F = \frac{I \cdot A}{c} \] 7. **Substituting Back into Pressure Equation**: Now substituting \( F \) back into the pressure equation: \[ P = \frac{F}{A} = \frac{I \cdot A / c}{A} = \frac{I}{c} \] 8. **Final Result**: Therefore, the pressure exerted by the electromagnetic wave on a non-reflecting surface is given by: \[ P = \frac{I}{c} \] ### Summary: The pressure exerted by an electromagnetic wave of intensity \( I \) on a non-reflecting surface is \( \frac{I}{c} \), where \( c \) is the speed of light.

To find the pressure exerted by an electromagnetic wave of intensity \( I \) on a non-reflecting surface, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: We are given an electromagnetic wave with intensity \( I \) (in watts per square meter) striking a non-reflecting surface. We need to determine the pressure exerted by this wave on the surface. 2. **Concept of Pressure**: ...
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