The ratio of contributions made by the eletric field and magnetic field components to the intensity of an `EM` wave is.

Options

A. `c : 1`
B. `c^(2) : 1`
C. `1 : 1`
D. `sqrt(c) : 1`

Answer

C

Explanation

Intensity in terms of electric field, `mu_(av) = 1/2 epsi_(0)E_(0)^(2)`
Intensity in term of magnetic field, `u_(av) = (1)/(2)(B_(0)^(2))/(mu_(0))`
Now, taking the intensity in terms of electric field.
`(U_(av))_("electric field") = 1/2 epsi_(0)E_(0)^(2)`
`rArr = 1/2 epsi_(0)(cB_(0))^(2), [:' E_(0) = cB_(0)]`
`= 1/2 epsi_(0)xx c^(2)B_(0)^(2)`
But, `c = (1)/(sqrt(mu_(0)epsi_(0)))`
`:. (mu_(av))_("electric acid") = 1/2 epsi_(0) xx (1)/(mu_(0)epsi_(0))B_(0)^(2) = (1)/(2)(B_(0)^(2))/(mu_(0))`
`= (mu_(av))_("magnetic field")`
Thus, the energy in electromagnetic