A point source of light S, placed at a
distance L in front of the centre of a mirror of width d,
hangs vertically on a wall. A man walks in front of the
mirror along a line parallel to th mirror at a distane
2L form it as shown.The greatest distance over which
he can see the image of the light source in the mirror is
(a) `d//2` (b) d (c) 2d (d) 3 d.

Explanation

The ray diagram will be as shown in figure given below.
HI=AB=d`rArr`DS=CD=d/2
Since, AH=2AD

`therefore` GH=2CD=2(d/2)=d
Similaly , IJ=d
`therefore` GJ=GH+HI+IJ=d+d+d=3d