Light of wavelength 300 nm in medium A enters into medium B througha plane surface. If frequency of light is `5xx10^(14)` Hz and `v_(a)//v_(b)=4//5`, then find absolute refractive indices of media A and B.

Explanation

Speed `v_(A)=vlamda_(A)=5xx10^(14)xx300xx10^(-9)=1.5xx10^(8)`m/s
Absolute refractive index, `mu_(A)=c/(v_(A))=(3xx10^(8))/(1.5xx10^(8))=2`
We have, `muprop1/v`
`therefore (mu_(A)/mu_(B))=v_(B)/v_(A) rArr 2/mu_(B)=5/4`
Refracticvve index, `mu_(B)=0.8xx2=1.6`