The diameter of the pupil of human eye is about `2 mm`. Human eye is most sensitive to the wavelength `555 nm`. Find the limit of resolution of human eye.

Explanation

Here, D=2mm=`2xx10^(-3)m,lamda=555nm=555xx10^(-9)m`
Limit of resolution,`d theta=(1.22lamda)/D=(1.22xx555xx10^(-9))/(2xx10^(-3))`
`=3.39xx10^(-4)`rad
`d theta=3.39xx10^(-4)xx(180/pi)^(0)=0.0194^(0)`
`=0.0194xx60` min=1.2 min