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When light rays are incident on a prism ...

When light rays are incident on a prism at an angle of `45^(@)`, the minimum deviation is obtained. If refractive index of the material of prism is `sqrt(2)`, then the angle of prism will be

A

`30^(@)`

B

`75^(@)`

C

`90^(@)`

D

`60^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B
(d) refractive index of prism,
`µ=(sin""(A+delta_(m))/2)/(sin""A/2)rArri=45^(@)=(A+delta_(m))/2`
So, `sin45^(@)/sin(A//2)=sqrt2`
So, `1/2=sin""A/2rArrA=60^(@)`
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