A ray of light passes from a medium A having refractive index 1.6. to the medium B having refractive index 1.5. The value of critical angle of medium
A is….

Options

A. `sin^(-1) sqrt((16)/(15))`
B. `sin^(-1) ((16)/(15))`
C. `sin^(-1) ((1)/(2))`
D. `sin^(-1) ((15)/(16))`

Answer

D

Explanation

As the law of refraction, we have
`(sin i_(C))/(sin 90^(@))=(1.5)/(1.6)`
`sin i_(C)=(15)/(16)`
Where, `i_(C)`=critical angle of medium, `A=sin^(1)(15)/(16)`