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If mu(v)=1.530 and mu(R)=1.5145, then di...

If `mu_(v)=1.530 and mu_(R)=1.5145`, then disperisve power of a crown glass is

A

0.0164

B

0.00701

C

0.0132

D

0.032

Text Solution

Verified by Experts

The correct Answer is:
A
Here, `mu_(V)=1.5230 and mu_(R)=1.5145`
Therefore, means refractive index.
`mu=(1.523+1.5145)/(2)=1.5187`
Now, disperisive power, `omega` is given by
`omega=(mu_(V)-mu_(R))/(mu-1)=(1.5230-1.5145)/(1.51787-1)=0.0164`
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