Find the kinetic energy, potential energy and total energy in
first and second orbit of hydrogen atom if potential energy in first orbit is taken
to be zero.

Explanation

The energy of electn in hydrogen atom hen it revolves innnth orbit is,
`E=(-13.6)/(n^(2))eV`
For `" " n=1, E_(1)=-13.60 eV`
Kinetic energy =-(Totla energy)
`K_(1)=-E_(1)=13.60 eV`
`U_(1)=2E_(1)=-27.20 eV`
`E_(2)=(E_(1))/((2)^(2))=-3.40 eV`
`K_(2)=3.40 eV`
and `" " U_(2)=-6.80 eV`
Now `U_(1)=0i.e.,` potenial energy has been inceased by `27.20 eV` So we, will increase U and E in all energy states by `27. 320eV` While kinetic energy will remin unchanged . Changed values jin tabulr from are as under.
`{:("Orbit",K(eV),U(eV),E(eV)),("First",13.60,0,13.60),("Second",3.40 ,20.40,23.80):}`