A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom transits form the upper level to the lower level.

Explanation

Here, difference of energy
`Delta=2.3 eV=2.3xx1.6xx10^(-19) J`
and Planck's constant `h=6.62xx10^(-34) J-s " " [ :. 1 eV =1.6xx10^(-19) J]`
Using the relation, `hv=DetlaE=E_(2)-E_(1)`
or `" " v=(DeltaE)/(h)=(2.3xx1.6xx10^(-19))/(6.62xx10^(-34))`
`0.553xx10^(15)Hz~~5.6xx10^(14) Hz`