An electron of a hydrogen like atom is in excited, state. If total energy of the electron is -4.6 eV, then evaluate
(i) the kinetic energy and
(ii) the de-Brogli wavelength of the electron .

Explanation

Given ,total energy of the electron `E=-4.6 EV`
(i) Kinetic energy of electron K=-(Total energy E,)
`rArr " " =-E=-(-4.6)=4.6 eV`
(ii) de- Brogile wavelength
`lambda_(d)=(h)/(sqrt(2 mK))=(6.6xx10^(-34))/(sqrt(2xx9.1xx10^(-31)xx4.6xx1.6xx10^(-19)))`
`0.57xx10^(-9)m=0.57 nm`