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Potential energy (PE(n)) and kinetic ene...

Potential energy `(PE_(n))` and kinetic energy `(KE_(n))` of electron in nth orbit are related as

A

`PE_(n)=KE_(n)`

B

`PE_(n)=-2KE_(n)`

C

`PE_(n)=2KE_(n)`

D

`PE_(n)=KE_(n)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the relationship between the potential energy (PE) and kinetic energy (KE) of an electron in the nth orbit, we can follow these steps: ### Step 1: Understand the definitions of KE and PE - The kinetic energy (KE) of an electron in the nth orbit is given by the formula: \[ KE_n = \frac{Z e^2}{8 \pi \epsilon_0 r_n} \] - The potential energy (PE) of the electron in the nth orbit is given by: \[ PE_n = -\frac{Z e^2}{4 \pi \epsilon_0 r_n} \] ### Step 2: Write the total energy (E) of the electron - The total energy (E) of the electron in the nth orbit is the sum of its kinetic and potential energy: \[ E_n = KE_n + PE_n \] - Substituting the expressions for KE and PE, we get: \[ E_n = \frac{Z e^2}{8 \pi \epsilon_0 r_n} - \frac{Z e^2}{4 \pi \epsilon_0 r_n} \] ### Step 3: Simplify the total energy expression - To combine the terms, we need a common denominator: \[ E_n = \frac{Z e^2}{8 \pi \epsilon_0 r_n} - \frac{2Z e^2}{8 \pi \epsilon_0 r_n} \] - This simplifies to: \[ E_n = -\frac{Z e^2}{8 \pi \epsilon_0 r_n} \] ### Step 4: Relate PE and KE - From the expressions for KE and PE, we can derive the relationship between them: - We have: \[ PE_n = -\frac{Z e^2}{4 \pi \epsilon_0 r_n} \] and \[ KE_n = \frac{Z e^2}{8 \pi \epsilon_0 r_n} \] - Now, we can express PE in terms of KE: \[ PE_n = -2 \times KE_n \] ### Conclusion Thus, the relationship between the potential energy and kinetic energy of an electron in the nth orbit is: \[ PE_n = -2 \times KE_n \]
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