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The ratio of the largest to shortest wav...

The ratio of the largest to shortest wavelength in Balmer series of hydrogen spectra is,

A

`(25)/(9)`

B

`(17)/(6)`

C

`(9)/(5)`

D

`(5)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
C
`" " lambdaprop(1)/((1/(n_(f^(2)))-1/n_(i^(2))))`
`" " (lambda_("longest"))/(lambda_("shortest"))=(((1)/(4)-(1)/(oo)))/((1/(4)-(1)/(9)))=((1//4))/((5//36))=(9)/(5)`
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