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For the Bohr's first orbit of circumfere...

For the Bohr's first orbit of circumference ` 2pi r` , the de - Broglie wavelength of revolving electron will be

A

`2pir`

B

`pir`

C

`(1)/(2pir)`

D

`(1)/(4pir)`

Text Solution

Verified by Experts

The correct Answer is:
A
According to Bohr's first postulate,
`" " mvr=(nh)/(2pi)`
`:. " " 2pir=n((h)/(mv))=nlambda`
For `" " n=1,lambda=2pir`
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