If `omega` the speed of electron in the nth orbit hydrogen atom, then

Options

A. `omega propn^(1//2)`
B. `omegaprop(1)/(n)`
C. `omega prop(1)/(n^(2))`
D. `omegaprop(1)/(n^(3))`

Answer

D

Explanation

`L_(n)=(nh)/(rpi) rArr Iomega=(nh)/(2pi)rArr (mr)^(2)omega=(nh)/(2pi)`
As `" " r prop n^(2)`
`:. " " omegaprop(1)/(n^(3))`