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When an electron in hydrogen atom is exc...

When an electron in hydrogen atom is excited, from its `4`th to `5`the stationary orbit, the change in angular momentum of electron is (Planck's constant: `h = 6.6 xx 10^(-34) J-s`)

A

`4.16xx10^(-34) J-s`

B

`3.32xx10^(-34)J-s`

C

`1.05xx10^(-34) J-s`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
Change in the angular momentum
`DeltaL=L_(2)-L_(1)(n_(2)h)/(2pi)=(n_(1)h)/(2pi)`
`DeltaL=(h)/(2pi)(n_(2)-n_(1))=(6.6xx10^(-34))/(2xx3.14)(5-4)=1.05xx10^(-34) J-s`
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