Ionization potential of hydrogen atom is `13.6 V`. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy `12.1 eV`. The spectral lines emitted by hydrogen atoms according to Bohr's theory will be

Options

A. One
B. Two
C. Three
D. Four

Answer

C

Explanation

Final energy of electron `=-13.6 +121=-1.51 eV`
This energy corresponds to third level i.e.,n=3
Hence, number of spectral lines emitted
`" " =(n(-1))/(2)=(3(3-1))/(2)=3`