If scattering particles are `56` for `90^(@)` angle than this will be at `60^(@)` angle

Options

A. 224
B. 256
C. 98
D. 108

Answer

A

Explanation

Accroding to scattering formula
`" " Nprop(1)/(sin^(4)(theta//2))rArr(N_(2))/(N_(1))=[(sin(theta_(1)//2))/(sin(theta_(2)//2))]^(4)`
`rArr" " (N_(2))/(N_(1))=[(sin.(90^(@))/(2))/(sin.(60^(@))/(2))]^(4)=[(sin 45^(@))/(sin30^(@))]^(4)`
`rArr " " N_(2)=(sqrt(2))^(4)xxN_(1)=4xx56=224`