In a Rutherford scattering experiment when a projectile of change `Z_(1)` and mass `M_(1)` approaches s target nucleus of change `Z_(2)` and mass `M_(2)`, te distance of closed approach is `r_(0)`. The energy of the projectile is

Options

A. directly proportianla to `M_(1)xxM_(2)`
B. directly proportianla to `Z_(1) Z_(2)`
C. directly proportianla to `Z_(1)`
D. directly proportianla to mass `M_(1)`

Answer

B

Explanation

The energy of the projectile will be equivalent to potential energy of the charge system
`" " E=(1)/(4piepsi_(0))((Z_(1)e)(Z_(2)e))/(r_(0))rArr "Energy",EpropZ_(1)Z_(2)`