If the wavelength of the first member of Blmer series of hydrogen spectrum is 6563Å A, then the wavelength of second member of Blamer series will be

Options

A. 1215Å
B. 4861Å
C. 6050Å
D. data given is insufficient to calculate the value

Answer

B

Explanation

`lambdaprop(1)/(((1)/(n_(f)^(2))-(1)/(n_(i)^(2))))`
`:." " (lambda)/(6563)=((1//4-1//9))/((1//4-1//16))=((5//36))/((12//64))`
`:. " " lambda=4861Å`