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Minimum excitation potential of Bohr's f...

Minimum excitation potential of Bohr's first orbit hydrogen atom is

A

13.6 V

B

`-13.6 V`

C

10.2 V

D

`-10 V`

Text Solution

Verified by Experts

The correct Answer is:
C

Energy of electron in ground state of hydrogen atom,
gt `" " E_(1)=-13.6eV " " [ :. E_(n)=(-13.6)/(n^(2))eV]`
`:.` Energy of electron in first excited state of hydrogen atom
`" " E_(2)=(-13.6)/(2^(2))=-3.4eV`
Hence, the excitation energy of hydrogen atom in first excited stat,
`" " E_(1)=E_(2)-E_(1)=-34-(-13.6)=10.2eV`
Therefore, excitation potential is 10.2 V.
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