The ionisation energy of hydrogen is 13.6 eV . The energy of the photon released when an electron jumps from the first excited state (n=2) to the ground state of hydrogen atom is

Options

A. 3.4 eV
B. 4.53 eV
C. 10.2 eV
D. 13.6eV

Answer

C

Explanation

The energy rquired to removed electron in the first excited state (n=2)
The energy of the photon `Rhc((1)/(1^(2))-(1)/(n^(2)))`
`rArr" " 13.6((1)/(4)-(1)/(4))=13.6((4-1)/(4))`
`" " =13.6 xx(3)/(4)=(40.8)/(4)=10.2eV`