In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelangth in the Balmer series is:

Options

A. `(5)/(27)`
B. `(3)/(23)`
C. `(7)/(29)`
D. `(9)/(31)`

Answer

A

Explanation

`(1)/(lambda)=R[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]`
For longest wavelelngth model states that an atom is a sphere of Lyman series `n_(1)=1 and n_(2)=2`
For longest wavelength of Balmer series `n_(1)2 and n_(2)=3`
`" " So (lambda_("Lyman"))/(lambda_("Balmer"))=(5)/(27)`