The `K_(alpha)` X-rays of moylydenum has a wavelength of `71xx10^(-12)m`. If the energy of molybdenum atom with molybdenum atom when an L-electron removed is `(hc=12.42xx10^(-7)eV)`

Options

A. 17.5 keV
B. 40.82 keV
C. 23.32 keV
D. 5.28 keV

Answer

D

Explanation

Given `E_(k)=23.32keV=23.32xx1.6xx10^(-19)eV`
`hc=12.42xx10^(-7) eV`
`lambda_(halpha)=71xx10^(-12)m `
`E_(L)-E_(K)=(hc)/(h_(kalpha))`
`E_(L)-23.32xx1.6xx10^(-19)=(12.42xx10^(7))/(71xx10^(-12))`
`rArr " " E_(L)=5.82 keV`