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An electrons of a stationary hydrogen at...

An electrons of a stationary hydrogen aton passes form the fifth enegry level to the ground level. The velocity that the atom acquired as a result of photon emission will be
`(m` is the mass of the electron, `R`, Rydberg constanrt and `h`, Planck's constant)

A

`(24hR)/(25m)`

B

`(25hR)/(24m)`

C

`(25m)/(24hR)`

D

`(24m)/(25hR)`

Text Solution

Verified by Experts

The correct Answer is:
A

Hence, `E_(5)-E_(1)=(hc)/(lambda)`
and `(Rhc)/(25)-Rhc=(hc)/(lambda)rArr(24)/(25)R=(1)/(lambda)`
But `p=(hc)/(lambda)anv=(h)/(mlambda)=(24)/(25)(Rhc)/(m)`
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