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The electron of a hydrogen atom revolves...

The electron of a hydrogen atom revolves the proton in a circuit nth of radius `r_(0) = (in_(0) n^(2)h^(2))/(pi m e^(2)) ` with a speed `upsilon_(0) =(e^(2))/(2 in_(0) nh)` The current the to circulating charge is proportional to

A

`e^(2)`

B

`e^(3)`

C

`e^(5)`

D

`e^(6)`

Text Solution

Verified by Experts

The correct Answer is:
C

Time period of electron , `T=(2mpir)/(v)=((2pixxepsi_(0)n^(2)h^(2))/(pime^(2)))/((e^(2))/(2epsi_(0)nh))`
`T=(4epsi_(0^(2))n^(3)h^(3))/(me^(4))`
Current, `i=(e)/(T)=(e)/((4epsi_(0)^(2)n^(3)h^(3))/(me^(4)))rArri=(me^(5))/(4epsi_(0)^(2)n^(3)h^(3))i.e., iprope^(5)`
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