A plane wavefront is incident at an angle of `37^(@)` with horizontal a boundary of refractive medium from air `(mu=1)` to a medium of refractive index `mu=3/2`. Find the angle of refracted wavefront with horizontal

Explanation

it has been given that incident wavefront makes `37^(@)` with horizontal. Hence, incident ray makes `37^(@)` with normal as the ray is perpendicular to the wavefront.

Now, by shell's law , `(sin 37^(@))/(sinr)=3/2`
`rArrsin r=2/3xx3/5=2/5`
`rArrr=sin^(-1)(2/5)` which is same as angle of refractive wavefront with horizontal.