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Light of wavelength 580 nm is incident o...

Light of wavelength 580 nm is incident on a slit having a width of `0.300` nm The viewing screen is 2.00 m from the slit. Find the positions of the first dark fringe and the width of the central bright fringe.

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To solve the problem, we need to find the position of the first dark fringe and the width of the central bright fringe for a single slit diffraction pattern. ### Given Data: - Wavelength of light, \( \lambda = 580 \, \text{nm} = 580 \times 10^{-9} \, \text{m} \) - Width of the slit, \( d = 0.300 \, \text{mm} = 0.300 \times 10^{-3} \, \text{m} \) - Distance from the slit to the screen, \( D = 2.00 \, \text{m} \) ### Step 1: Find the Position of the First Dark Fringe ...
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