If two waves represented by `y_(1)=4sinomegat` and `y_(2)=3sin(omegat+(pi)/(3))` interfere at a point find out the amplitude of the resulting wave

Options

A. 7
B. 6
C. 5
D. `3.5`

Answer

B

Explanation

Here phase difference `phi=pi//3`
So, amplitude of resulting wave
`A=sqrt(a_(1)^(2)+a_(2)^(2)+2a_(1)a_(2) cos phi)`
`=sqrt(4^(2)+3^(2)+2xx4xx3 cos pi//3)approx 6`