In Young's double slit experiment, the aperture screen distance is `2m`. The fringe width is `1mm`. Light of `600nm` is used. If a thin plate of glass `(mu=1.5)` of thickness `0.06mm` is placed over one of the slits, then there will be a lateral displacement of the fringes by

Options

A. 0 cm
B. 5 cm
C. 10 cm
D. 15 cm

Answer

B

Explanation

When thin plate of glass is introduced, then lateral displacement of fringes
`=beta/lambda(mu-1)t`
`=(1xx10^(-3))/(600xx10^(-9))(1.5-1)xx0.06xx10^(-3)=1/20m=5cm`