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A light wave is incident normally over a...

A light wave is incident normally over a slit of width `24xx10^-5cm`. The angular position of second dark fringe from the central maxima is `30^@`. What is the wavelength of light?

A

`6000 Å`

B

`5000 Å`

C

`3000 Å`

D

`1500 Å`

Text Solution

Verified by Experts

The correct Answer is:
A
For nth dark fringe, in single slit
`a sin theta=nlambda`
For second dark fringe, `a sin theta=2lambda`
`So, 24xx10^(-5)xx10^(-2)xxsin 30^(@)=2lambda`
`:. lambda=6xx10^(-7)m=6000Å`
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