Light is incident on a glass surface at polarising angle of `57.5^(@)` Then the angle between the incident ray and the refracted ray is

Options

A. `57.5^(@)`
B. `115^(@)`
C. `65^(@)`
D. `205^(@)`

Explanation

To solve the problem of finding the angle between the incident ray and the reflected ray when light is incident on a glass surface at a polarizing angle of 57.5 degrees, we can follow these steps:

### Step 1: Understand the Polarizing Angle
The polarizing angle (also known as Brewster's angle) is the angle at which light with a particular polarization is perfectly transmitted through a transparent dielectric surface, with no reflection. The polarizing angle is given as 57.5 degrees.

### Step 2: Identify the Angles
When light is incident at the polarizing angle (let's denote it as \( \theta_p \)), the angle of incidence \( i \) is equal to the polarizing angle:
\[ i = \theta_p = 57.5^\circ \]

### Step 3: Apply Snell's Law
According to Snell's Law, the relationship between the angles of incidence and refraction is given by:
\[ n_1 \sin(i) = n_2 \sin(r) \]
Where:
- \( n_1 \) is the refractive index of the first medium (air, approximately 1),
- \( n_2 \) is the refractive index of the second medium (glass, typically around 1.5),
- \( i \) is the angle of incidence,
- \( r \) is the angle of refraction.

However, for this problem, we are more interested in the relationship between the incident ray and the reflected ray.

### Step 4: Determine the Angle of Reflection
According to the law of reflection, the angle of reflection \( r \) is equal to the angle of incidence:
\[ r = i = 57.5^\circ \]

### Step 5: Calculate the Angle Between Incident Ray and Reflected Ray
The angle between the incident ray and the reflected ray can be determined by considering that both angles are measured from the normal line. Therefore, the total angle between the incident ray and the reflected ray is:
\[ \text{Angle between incident ray and reflected ray} = i + r \]
\[ = 57.5^\circ + 57.5^\circ = 115^\circ \]

### Final Answer
The angle between the incident ray and the reflected ray is:
\[ 115^\circ \]