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Two slits at a distance of 1mm are illum...

Two slits at a distance of `1mm` are illuminated by a light of wavelength `6.5xx10^-7m`. The interference fringes are observed on a screen placed at a distance of `1m`. The distance between third dark fringe and fifth bright fringe will be

A

`0.65 mm`

B

`1.63 mm`

C

`3.25 mm`

D

`4.88 mm`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaY=(5lambdaD)/d-(5lambdaD)/(2d)=(5lambdaD)/(2d)`
`=(5xx6.5xx10^(-7)xx1)/(2xx10^(-3))m=1.63mm`
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